Question

The particle is executing S.H.M. on a line 4 cms long. If its velocity at its mean position is 12 cm/sec, its frequency in Hertz will be :

• A. $\frac{2\pi }{3}$
• B. $\frac{3}{2\pi }$
• C. $\frac{\pi }{3}$
• D. $\frac{3}{\pi }$

Answer 1

Answer: (B)

$\frac{3}{2\pi }$

Given,

$A=4cm$

$v=12cm/s$ at $x=0$ mean position

The velocity of particle performing S.H.M is given by

$v=\omega \sqrt{A^2-x^2}$

$12=\omega \sqrt{4^2-0}$

$12=4\omega$

$\omega =2\pi f=3$

$f=\frac{3}{2\pi }$

The correct option is B.