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Question

The particular solution for the differential equaiton d2ydx2+3dydx+2y=5cosx is

A
0.5cosx+1.5sinx
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B
1.5cosx+0.5sinx
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C
1.5sinx
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D
0.5cosx
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Solution

The correct option is A 0.5cosx+1.5sinx
Given DE is
d2ydx2+3dydx+2y=5cosx
P.I=1(D2+3D+2).5cosx
Using
=1f(D2)cos(ax+b)=1f(a2)cos(ax+b)
=P.I=51(12)+3D+2cosx
=5(3D+1)cosx
=5×3D19D21cosx
=5×3D19(1)1cosx
=510×(3D1)cosx
P.I=12×(3D1)cosx
=12×[(3(sinx)cosx]
P.I=1.5sinx+0.5cosx

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