The passage of current through a solution of certain electrolyte results in the formation of hydrogen at cathode and chlorine at anode. The solution is:

Cupric chloride in water

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Sodium chloride in water

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Sulphuric acid in water

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Water

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Solution

The correct option is B Sodium chloride in water
Reduction potential of
$H^{+} > N a^{+}$
and oxidation potential of
$C l^{-} > O H^{-}$
$∴$ electrolysis, $H_{2}$ is released at cathode and $C l_{2}$ at anode
$2 e^{-} + 2 H^{+} \to H_{2}$
$2 C l^{-} \to C l_{2} + 2 e^{-}$

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Q. The passage of current liberates

H_{2}

at cathode and

C l_{2}

at anode. The solution is:

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The passage of current through a solution of certain electrolyte results in the formation of hydrogen at cathode and chlorine at anode. The solution is:

The correct option is B Sodium chloride in waterReduction potential of H+>Na+and oxidation potential of Cl−>OH−∴ electrolysis, H2 is released at cathode and Cl2 at anode2e−+2H+→H22Cl−→Cl2+2e−

The correct option is B Sodium chloride in water
Reduction potential of
$H^{+} > N a^{+}$
and oxidation potential of
$C l^{-} > O H^{-}$
$∴$ electrolysis, $H_{2}$ is released at cathode and $C l_{2}$ at anode
$2 e^{-} + 2 H^{+} \to H_{2}$
$2 C l^{-} \to C l_{2} + 2 e^{-}$