The path difference between the two waves is y1=a1sin(ωt−2πxλ) and y2=a2cos(ωt−2πxλ+ϕ) is
A
2πλ(ϕ−π2)
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B
λ2π(ϕ+π2)
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C
2πλϕ
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D
λ2πϕ
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Solution
The correct option is Bλ2π(ϕ+π2)
Given, y1=a1sin(ωt−2πxλ)
And y2=a2cos(ωt−2πxλ+ϕ) =a2sin(ωt−2πxλ+ϕ+π2)
So, phase difference =ϕ+π2
And path difference Δx=λ2π (phase difference) ∴Δx=λ2π(ϕ+π2)
Final answer: (b)