Question

The path followed by a body projected along y-axis is given as by $y=\sqrt{3}x-\left(\frac{1}{2}\right)x^2$, if g = 10 m/s, then the initial velocity of projectile will be – (x and y are in m)

• A.
• B.
• C.
• D.

Answer 1

The correct option is B

By comparing the coefficient of $x^2$ in given equation with standard equation

$y=xtan\theta -\frac{g{x}^2}{2u^{2}co{s}^2\theta }.\frac{g}{2u^{2}co{s}^2\theta }=\frac{1}{2}tan\theta =\sqrt{3}$

Substituting $\theta ={60}^{\circ }wegetu=2\sqrt{10}m/sec.$