Question

The path of train $A$ is given by the equation $3x+4y-12=0$ and the path of another train $B$ is given by the equation $6x+8y-48=0$. Represent this situation graphically.

Answer 1

Equation of path (A) : $3x+4y-12=0$

$\Rightarrow$x-intercept of (A) =4

$\Rightarrow$y-intercept of (A) =3

$\Rightarrow$Slope of (A) $=\frac{-3}{4}$

Equation of path (B) : $6x+8y-48=0$

$\Rightarrow$x-intercept of (B) =8

$\Rightarrow$y-intercept of (B) =6

$\Rightarrow$Slope of (B) $=\frac{-6}{8}=\frac{-3}{4}$

$\Rightarrow$Both the paths are parallel as there slopes are equal