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Question
The PE of three objects of masses 1kg,2kg and 3kg placed at the three vertices of an equilateral triangle of side 20cm is
The PE of three objects of masses 1kg,2kg and 3kg placed at the three vertices of an equilateral triangle of side 20cm is
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Solution
The correct option is D −55G
Givenm1=1kgm2=2kgm3=3kgr=20cm
Potential Energy is given by:PE=Gm1M2r
Total potential energy is the sum of potential energies between each of the two pairs.
∴PE=PE1+PE2+PE3
⇒PE=−Gr(m1m2+m2m3+m3m1)=−G0.2(2+6+3)=−55G
Given
m1=1kgm2=2kgm3=3kgr=20cm
PE=Gm1M2r
Total potential energy is the sum of potential energies between each of the two pairs.
∴PE=PE1+PE2+PE3
⇒PE=−Gr(m1m2+m2m3+m3m1)=−G0.2(2+6+3)=−55G
Total potential energy is the sum of potential energies between each of the two pairs.
∴PE=PE1+PE2+PE3
⇒PE=−Gr(m1m2+m2m3+m3m1)=−G0.2(2+6+3)=−55G
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