Question

The peak value of an Alternating current is $6$ amp, then r.m.s. value of current will be

• A. $3$ A
• B. $3\sqrt{3}$ A
• C. $3\sqrt{2}$ A
• D. $2\sqrt{3}$ A

Answer 1

Answer: (C)

$3\sqrt{2}$ A

As we know,

$i_{r.m.s}=\frac{6}{\sqrt{2}}=3\sqrt{2}A$