Question

The peak voltage in a $220\text{V}$ a.c. source is-

• A. $220\text{V}$
• B. About $160\text{V}$
• C. About $310\text{V}$
• D. $440\text{V}$

Answer 1

The correct option is C About $310\text{V}$

Given,

$V_{rms}=220\text{V}$

As we know, $V_{rms}=\frac{V_0}{\sqrt{2}}$

$\Rightarrow V_0=\sqrt{2}{V}_{\text{rms}}$

$\therefore V_0=\sqrt{2}\times 220=311.08\text{V}\text{(or)}$

$\therefore V_0\approx 310\text{V}$

<!--td {border: 1px solid #ccc;}br {mso-data-placement:same-cell;}--> Hence, $\left(C\right)$ is the correct answer.