Question

The peak voltage in a $220\text{V}$ AC source is -

Take $\sqrt{2}=1.414$

• A. $220\text{V}$
• B. $320\text{V}$
• C. $311\text{V}$
• D. $430\text{V}$

Answer 1

The correct option is C $311\text{V}$

Given:

RMS voltage, $E_{rms}=220\text{V}$

We know that, peak voltage,

$E_0=\sqrt{2}{E}_{rms}=1.414\times 220=311\text{V}$