Question

The peak voltage in a 220 V, 50 Hz $AC$ source is

• A. 220 V
• B. about 160 V
• C. about 310 V
• D. 440 V

Answer 1

The correct option is C about 310 V

The voltage rating is the rms(root mean square) value of voltage. Therefore,

$V_{peak}=\sqrt{2}{V}_{Rated}$
$=\sqrt{2}\times 220=311V$