Question

The peak voltage in the output of a half-wave diode rectifier fed with a sinusoidal signal without filter is 10V. The d.c. component of the output voltage is

• A. $10/\sqrt{2}V$
• B. $10/\pi V$
• C. 10 V
• D. $20/\pi V$

Answer 1

Answer: (B)

$10/\pi V$

Here, the peak voltage in the output of a half-wave diode rectifier fed with a sinusoidal signal without filter is 10V. Hence, the d.c. component of the output voltage is given by:

$V_{av}\frac{{\int }_0^{\pi }10sin\left(\omega t\right)}{2\pi }$

$=\frac{10}{2\pi }(-cos\theta ){|}_0^{\pi }=\frac{2\times 10}{2\pi }$

$=\frac{10}{\pi }V$