Question

The peak voltage of a 220 V AC source is

(a) 220 V
(b) about 160 V
(c) about 310 V
(d) 440 V

Answer 1

(c) about 310 V

Given:
V_rms = 220 V
The peak value of voltage is given by,
$V_p=\sqrt{2}\times V_{rms}=1.414\times 220=311\mathrm{V}$