The peak voltage of an ac supply is $440 V$ , then its rms voltage is then

31.11 V

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311.1 V

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41.11 V

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411.1 V

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Solution

The correct option is D $311.1 V$
Given: The peak voltage of the supply is $V_{m} = 440 V$

The RMS voltage of the supply is given by:
$∴ V_{r m s} = \frac{V_{m}}{\sqrt{2}} = \frac{440}{\sqrt{2}} = 311.1 V$

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