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The pedal equ...

Question

The pedal equation of the circle $x^{2} + y^{2} = 4$ with regard to the point $(2, 0)$

r^{2} = 4

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4 p = r^{2}

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p^{2} = 4 r

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p = 4 r^{2}

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Solution

The correct option is B $4 p = r^{2}$
Teh pedal equation of a circle with radius $a$ with respect to a point on a circumference is $p a = r^{2}$
Given pedal point $(2, 0)$ lies on the circumference of the circle $x^{2} + y^{2} = 4$
$∴$ Required pedal equation is $4 p = r^{2}$
Hence, option B.

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