The pendulum of a clock is replaced by a spring-mass system with the spring having spring constant $0.1 N m^{- 1.}$ What mass should be attached to the spring ?

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Solution

$k = 0.1 N / m$

$T = 2 π \sqrt{(\frac{m}{k})} = 2 s e c$

[Time period of pendulum of a clock = 2 sec ]

So, $π^{2} (\frac{m}{k}) = 1$

$∴ m = \frac{k}{π^{2}} = \frac{0.1}{10}$

$= 0.01 k g \approx 10 g m$

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The pendulum of a clock is replaced by a spring-mass system with the spring having spring constant 0.1 N m−1. What mass should be attached to the spring ?

k=0.1 N/m T=2π √(mk)=2 sec [Time period of pendulum of a clock = 2 sec ] So, π2(mk)=1 ∴ m=kπ2=0.110 =0.01 kg≈10 gm

The pendulum of a clock is replaced by a spring-mass system with the spring having spring constant $0.1 N m^{- 1.}$ What mass should be attached to the spring ?

$k = 0.1 N / m$

$T = 2 π \sqrt{(\frac{m}{k})} = 2 s e c$

[Time period of pendulum of a clock = 2 sec ]

So, $π^{2} (\frac{m}{k}) = 1$

$∴ m = \frac{k}{π^{2}} = \frac{0.1}{10}$

$= 0.01 k g \approx 10 g m$