The penultimate and outermost orbit of an element contains 10 and 2 electrons respectively. If the outermost orbit is the fourth orbit, then the atomic number of the element should be:
A
12
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B
22
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C
32
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D
40
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Solution
The correct option is B 22 Given 4th orbit has 2 electrons. 3rd orbit has 10 electrons. 1stand2nd shells are completely filled and the number of electrons are 2 and 8 respectively. Hence the total number of electrons =2+8+10+2=22 So, the atomic number will be 22.