The penultimate and outermost orbit of an element contains 10 and 2 electrons respectively. If the outermost orbit is the fourth orbit, then the atomic number of the element should be:

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Solution

The correct option is B 22
Given
$4^{t h}$ orbit has 2 electrons.
$3^{r d}$ orbit has 10 electrons.
$1^{s t} and$ $2^{n d}$ shells are completely filled and the number of electrons are 2 and 8 respectively.
Hence the total number of electrons $= 2 + 8 + 10 + 2 = 22$
So, the atomic number will be 22.

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Atomic Number and Mass Number

Standard XI Chemistry

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The penultimate and outermost orbit of an element contains 10 and 2 electrons respectively. If the outermost orbit is the fourth orbit, then the atomic number of the element should be:

The correct option is B 22Given 4th orbit has 2 electrons. 3rd orbit has 10 electrons. 1stand 2nd shells are completely filled and the number of electrons are 2 and 8 respectively. Hence the total number of electrons =2+8+10+2 =22 So, the atomic number will be 22.