The percent composition by mass of the phosphorus in calcium phosphate $C a_{3} (P O_{4})_{2}$ is $x$ . Then, the value of $x$ is :

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Solution

The molar mass of $C a_{3} (P O_{4})_{2} = 310$ g
% $C a$ $= 120 \times \frac{100}{310} = 38.71$
% $P$ $= 2 \times 31 \times \frac{100}{310} = 20$
% $O$ $= 8 \times 16 \times \frac{100}{310} = 41.29$
Thus, $x$ is $20$ .

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