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Empirical & Molecular Formula

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Question

The percentage by mole of ${N O}_{2} (g)$ in a mixture of ${N O}_{2} (g)$ and $N O (g)$ having average molecular mass 34 is :

A

25%

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B

20%

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C

40%

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D

75%

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Solution

The correct option is A 25%
Assume mole % of $N O_{2} = x$
Then, mole % of $N O = 100 - x$
So, avg. atomic mass of mixture $= \frac{x \times 46 + (100 - x) \times 30}{100}$ $= 34$ (given)
Hence, $x = 25$ %

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