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Enthalpy of Solution

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Question

The percentage composition of Mohr's salt is as follows. Fe²+=14.32% NH4=9.20% SO4²‐=49% REST being water of crystallization.Find the empirical formula of Mohr's salt.

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Solution

Elements
Percentage
Atomic mass
Relative mass of atoms
Simplest ratio

$F e$ 14.32% 56 $\frac{14.32}{56} = 0.25$ $\frac{0.25}{0.25} = 1$
${N H}_{4}$ 9.20% 18 $\frac{9.20}{18} = 0.50$ $\frac{0.5}{0.25} = 2$
$H_{2} O$ 27.57% 18 $\frac{27.57}{18} = 1.5$ $\frac{1.5}{0.25} = 6$
${S O}_{4}$ 49% 96 $\frac{49}{96} = 0.5$ $\frac{0.5}{0.25} = 2$
Empirical formula = $F e {({N H}_{4})}_{2} {(H_{2} O)}_{6} S O_{2}$

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