Speed of transverse wave is
v=√Tμ Taking log on both sides lnv=12lnT−12lnμ Or, Δvv=12ΔTT ⇒Δvv×100=12ΔTT×100=12×4 [μ is constant for a string ] ∴Δvv×100=2%
The extension in a string obeying Hooke's law is x. The speed of a transverse wave in a stretched string is v. If the extension in the string is increased to 1.5x, the speed of the wave will be