Question

The percentage of available chlorine in a sample of bleaching powder, $CaOC{l}_2.2H_{2}O$, is:

• A. 30
• B. 50
• C. 43.5
• D. 59.9

Answer 1

The correct option is C 43.5

CaOCl${}_2$. 2H${}_2$O $\to$Cl${}_2$

1 mole of CaOCl${}_2$. 2H${}_2$O gives 1 mole Cl${}_2$

163 g of sample gives 71g of available Chlorine

Therefore, % available chlorine = $\frac{71}{163}\times$ 100= 43.5%