Question

The percentage of C,H and N in an organic compound are 40%, 13.3% and 46.7% respectively then emprirical formula is :

• A. $C_3{H}_{13}{N}_3$
• B. $C{H}_{2}N$
• C. $C{H}_{4}N$
• D. $C{H}_{6}N$

Answer 1

The correct option is C $C{H}_{4}N$

Table of empirical formula

Element	$\%$ composition	At.Wt	Molar Ratio	Simplest Ratio
C	40.0	12	40/12=3.33	3.33/3.33=1
H	13.3	1	13.3/1=13.3	13.3/3/33=4
N	46.7	14	46.7/14=3.33	3.33/3.33=1

Thus, empirical formula of compound is $C{H}_{4}N$.

Hence the correct answer is option (c).