The percentage of metals in a mine of lead ore is $60$ . Now the percentage of silver is $\frac{3}{4}$ % of metals and the rest is lead. If the mass of ore extracted from this mine is $8000 k g$ , the mass (in kg.) of lead is:

4763

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4764

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4762

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Solution

The correct option is A $4764$
Given mass of lead ore $(i n k g) = 8000$
Mass of metals in ore $(i n k g) = 60 %$ of ore.
$= \frac{60}{100} \times 8000 = 4800$
Mass of silver $= 3 / 4 %$ of mass of metals
$= \frac{3}{4} \times \frac{1}{100} \times 4800 = 36$
As lead is metal, so
Mass of $P b =$ Mass of metal-Mass of Silver
$= 4800 - 36 = 4764$

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The percentage of metals in a mine of lead ore is 60. Now the percentage of silver is 34% of metals and the rest is lead. If the mass of ore extracted from this mine is 8000 kg, the mass (in kg.) of lead is:

The correct option is A 4764Given mass of lead ore (in kg)=8000Mass of metals in ore (in kg)=60%of ore.=60100×8000=4800Mass of silver=3/4% of mass of metals=34×1100×4800=36As lead is metal, soMass of Pb=Mass of metal-Mass of Silver=4800−36=4764

The percentage of metals in a mine of lead ore is $60$ . Now the percentage of silver is $\frac{3}{4}$ % of metals and the rest is lead. If the mass of ore extracted from this mine is $8000 k g$ , the mass (in kg.) of lead is: