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Electronegativity and Hybridisation

The percentag...

Question

The percentage of p-character in the orbitals forming p – p bonds in $P_{4}$ is

A

25

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B

33

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C

50

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D

75

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Solution

The correct option is D
75

In $P_{4}$ , each p is $s p^{3}$ hybridized so that percentage of p-character in these orbitals is $75 %$ .

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Electronegativity and Hybridisation

Standard XII Chemistry

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