You visited us 1 times! Enjoying our articles? Unlock Full Access!

Allotropes of Phosphorus

The percentag...

Question

The percentage of s-character in the orbital forming $P - S$ bonds in $P_{4} S_{3}$ is:

25 %

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

33 %

No worries! We‘ve got your back. Try BYJU‘S free classes today!

75 %

No worries! We‘ve got your back. Try BYJU‘S free classes today!

50 %

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is A $25 %$
The percentage of s-character in the orbital forming $P - S$ bonds in $P_{4} S_{3}$ is $25 %$ due to $s p^{3}$ hybridization.

Suggest Corrections

Similar questions

The percentage of p-character in forming P-P bonds in P₄ molecule is:

The percentage of p-character in the orbitals forming p – p bonds in $P_{4}$ is

N H_{3}

S_{1} : S e F_{6}

P F_{5}

s p^{3} d^{2}

S_{2}

S_{8}

P_{4}

S_{3} :

[C o (N H_{3})_{6}]^{3 +}

P_{4}

P_{4}

Join BYJU'S Learning Program