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Atomic Number and Mass Number

The percentag...

Question

The percentage of sulphur in an organic compound whose 0.32g produces 0.233g of $B a S O_{4}$ [atomic weight of Ba= 137, S=32] is

1.0

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10.0

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23.5

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32.1

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Solution

The correct option is B
10.0

$% o f S = \frac{32}{233} \times \frac{0.233}{0.32} \times 100 = 10$

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Similar questions

B a S O_{4}

B a S O_{4}

S

0.16 g

0.233 g

B a S O_{4}

0.1254

0.1292

B a = 137; S = 32; O = 16

0.32

0.233

B a S O_{4}

B a = 137, S = 32, O = 16

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