The percentage value of nitrogen in urea is about :

46

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85

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18

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28

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Solution

The correct option is A $46$
The formula of urea is $N H_{2} C O N H_{2}$
$W_{N} = 28$
$W_{C} = 12$
$W_{O} = 16$
$W_{H} = 4$
In $60$ g urea, $W_{N} = 28 g$
$100$ g urea, $W_{N}$ is = $\frac{28}{60} \times 100 = 46 %$

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