The perimeter (in cm) of a square circumscribing a circle of radius $a$ cm , is

8 a

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4 a

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2 a

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16 a

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Solution

The correct option is A $8 a$

Let $A B C D$ is a square circumscribing a circle of radius $^{'} a^{'} c m$ .
The side of square $A B C D$ = Diameter of circle
$\Rightarrow A B = 2 a$
Therefore, perimeter of square $A B (1) = 4 \times A B = 4 \times 2 a = 8 a c m$

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