Question

The perimeter of a parallelogram is $92cm$. If one side is greater than its adjacent side by $10cm$, find its sides.

Answer 1

We know that in parallelogram opposite sides are equal.

Let shorter side of parallelogram be $a$

Then, greater side will be $a+10$

Perimeter of parallelogram $=2\left[\right(a)+(a+10\left)\right]$

$\Rightarrow$ $92=2[2a+10]$

$\Rightarrow$ $92=4a+20$

$\Rightarrow$ $4a=72$

$\therefore$ $a=\frac{72}{4}=18cm$

$\Rightarrow$ Greater side $=18+10=28cm$

$\therefore$ The sides of parallelogram are $18cm$ and $28cm$.