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Question

The perimeter of a quadrant of a circle of radius r is:

A
πr2
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B
2πr
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C
r2[π+4]
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D
2πr+r2
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Solution

The correct option is B r2[π+4]
Perimeter of quadrant of a circle =14×2π×r+2r
=πr2+2r=r2[π+4]

908724_83816_ans_c4dbb67b5fe24cb1a6dd4cb2024a9efa.png

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