The perimeter of a rectangle, $(16 x^{3} - 6 x^{2} + 12 x + 4)$ . If one of its sides is $(8 x^{2} + 3 x)$ , then the other side is

16 x^{3} - 14 x^{2} + a x + 4

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8 x^{3} - 11 x^{2} + 3 x + 2

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16 x^{3} + 14 x^{2} + a x - 4

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8 x^{3} + 11 x^{2} + 3 x - 2

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Solution

The correct option is B $8 x^{3} - 11 x^{2} + 3 x + 2$
Perimeter of rectangle $= 16 x^{3} - 6 x^{2} + 12 x + 4$
$2 (l + b) = 16 x^{3} - 6 x^{2} + 12 x + 4$
$l + b = 8 x^{3} - 3 x^{2} + 6 x + 2$
$b = (8 x^{3} - 3 x^{2} + 6 x + 2) - (8 x^{2} + 3 x)$
$= 8 x^{3} - 3 x^{2} + 6 x + 2 - 8 x^{2} - 3 x$
$= 8 x^{3} - 11 x^{2} + 3 x + 2$

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