The perimeter of a rectangle is 12 metres. The length is 3 more than twice its width. What is the relation between length and width in terms of equation.
A
l=3+2b
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B
l+b=12
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C
l=2b−3
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D
b=2l−3
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Solution
The correct option is Al=3+2b Let length and width be l and b. 2(l+b)=12 l+b=6 l=3+2b 6−b=3+2b 3b=3 b=1,l=5 Area =lb=1×5=5