Question

The perimeter of a rectangle is 12 metres. The length is 3 more than twice its width.
How many such rectangles are possible?

• A. One
• B. Two
• C. Infinitely many
• D. No such rectangle possible

Answer 1

The correct option is A One

Let length and width be l and b.
$2(l+b)=12$
$l+b=6$
$l=3+2b$
$6-b=3+2b$
$3b=3$
$b=1,l=5$
only one solution is possible so only one rectangle is possible.