The perimeter of a rectangle is 34 cm. If its length is 7 cm, then its breadth is

$10 c m$

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$14 c m$

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$20 c m$

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$5 c m$

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Solution

The correct option is A
$10 c m$

We know that if $l$ is the length of the rectangle and $b$ is its breadth, then its perimeter is given by

$P = l + b + l + b = (2 \times l) + (2 \times b)$

Given $P = 34 c m a n d l = 7 c m$

Then,

$P = (2 \times l) + (2 \times b)$

$b = \frac{P - (2 \times l)}{2}$

i.e., $b = \frac{34 - (2 \times 7)}{2} = 10 c m$

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The perimeter of a rectangle is 34 cm. If its length is 7 cm, then its breadth is

The correct option is A 10cm We know that if l is the length of the rectangle and b is its breadth, then its perimeter is given by P=l+b+l+b=(2×l)+(2×b) Given P=34cmandl=7cm Then, P=(2×l)+(2×b) b=P−(2×l)2 i.e., b=34−(2×7)2=10cm