Question

The Perimeter of a rectangle is 54 cm. The area of another rectangle is 44 $c{m}^2$.

The lengths of both rectangles are same. What is the average of the width of both rectangles?

• A. 2.5 : 1.5
• B. 2 : 3
• C. 3 : 5
• D. Cannot be determined

Answer 1

The correct option is D

Cannot be determined

Perimeter of 1st rectangle = 54 cm

Let length be l and breadth be b1.

l + b1 = $\frac{54}{2}$ = 27

l = 27 - b1

Let breadth of the other rectangle be b2.

l $\times$ b2 = 44

Substituting the value of l we get :

(27 - b1) $\times$ b2 = 44

$\Rightarrow$ 27b2 - b1b2 = 44

Since , the equation cannot help us find the value of $\frac{b1+b2}{2}$

$\therefore$ The average of widths Cannot be determined from the given data