The perimeter of a rectangle is $60 c m$ . If one of the sides of the rectangle is $12 c m$ , find its area.

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Solution

Perimeter = 2(l+b)
So 2(12+b) = 60
12+b = 30
so b = 18 cm
Area = lb
$= 12 \times 18$
=216 $c m^{2}$

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The perimeter of a rectangle is 60 cm. If one of the sides of the rectangle is 12 cm, find its area.

Perimeter = 2(l+b)So 2(12+b) = 6012+b = 30so b = 18 cm Area = lb =12×18=216 cm2

The perimeter of a rectangle is $60 c m$ . If one of the sides of the rectangle is $12 c m$ , find its area.

Perimeter = 2(l+b)
So 2(12+b) = 60
12+b = 30
so b = 18 cm
Area = lb
$= 12 \times 18$
=216 $c m^{2}$