The perimeter of a rectangle whose length is twice the breadth is $24$ cm. Then the area of the rectangle is

28

sq. cm

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32

sq. cm

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36

sq. cm

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42

sq. cm

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Solution

The correct option is B $32$ sq. cm
Let the width be $x$ , then length $= 2 x$
$∴ P e r i m e t e r = x + 2 x + x + 2 x = 24$
$\Rightarrow x = 4$
Hence width $= 4$ and length $= 8$
$∴ R e q u i r e d a r e a = 8 \times 4 = 32 s q . c m .$

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