Question

The perimeter of a rectangular is $104$ m and its area is $640m^2$. Find its length and breadth.

Answer 1

Atp,

$2(l+b)=104$

$⟹l+b=52$..............(i)

$lb=640$

Putting $l=\frac{640}{b}$ in equation(i), we get

$b^2-52b+640=0$

$(b-32)(b-20)=0$

Hence, b is either $20cm$ or $32cm$

similarily l is either $32cm$ or $20cm$

$(l,b)=(20,32)$ or $(32,20)$