Question

The perimeter of a rectangular table is $28$ m , whereas its area is $48$$m^2$ . What is the length of its diagonal ?

• A. $5$ m
• B. $10$ m
• C. $12$ m
• D. $12.5$ m

Answer 1

Answer: (B)

$10$ m

Perimeter of Rectangle $=28$ m

2( length +Breadth ) $=28$ m

length + breadth $=14$ m ( 1 ) equation

Area of Rectangle $=48m^2$

Length × breadth $=48m^2$ ( 2 ) equation

On 1 equation,

length + Breadth $=14$

lets Square on both sides,

Length${}^2+$Breadth${}^2+2\left(48\right)=196m^2$

Have put the value of length × breadth

Length${}^2+$ breadth${}^2=196-96$

Length${}^2+$ breadth${}^2=100$

We know,

diagonal of Rectangle $=\sqrt{lengt{h}^2+breadt{h}^2}$

So, diagonal =$\sqrt{100}m$

Length of diagonal $=10$ m.