The perimeter of a rhombus is 100 cm and one of the diagonals is 40 cm, Then the area of the rhombus is
Given that, perimeter of rhombus is 100cm and one diagonal 40cm
Perimeter of rhombus=4×side
So side=25cm
And we know that in a rhombus diagonal divides rhombus in two eauilateral triangle.
Area of one triangle:- s=(25+25+40)/2=45
So area=(s×(s-a)× (s-b)×(s-c))^1/2
= (45×(45-40)×(45-25)×(45-25))^1/2
=300cm2
So total area is 300×2=600cm^2
Hence, this is the answer.