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Question

The perimeter of a rhombus is 180 cm and one of its diagonals is 72 cm. Find the length of the other diagonal and the area of the rhombus.

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Solution



Let ABCD be a rhombus whose diagonals AC and BD intersect at a point O.Let the length of the diagonal AC be 72 cm and the side of the rhombus be x cm.Perimeter of the rhombus=4x cmBut it is given that the perimeter of the rhombus is180 cm. 4x=180 x=1804x=45Hence, the length of the side of the rhombus is 45 cm.We know that the diagonals of the rhombus bisect each other at right angles. AO=12ACAO=12×72cmAO=36 cmFrom right AOB, we have: BO2 =AB2-AO2BO2=452-362BO2=2025-1296BO2=729BO=729BO=27 cm BD=2×BOBD=2×27cmBD=54 cmHence, the length of the other diagonal is 54 cm.Area of the rhombus=12×72×54 cm2
=1944 cm2

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