The perimeter of a rhombus is $40 c m$ and the length of one diagonal is $16 c m$ . Find the length of the other diagonal.

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Solution

The correct option is A $12$ cm
Perimeter $= 4 s i d e = 4 \frac{1}{2} \sqrt{d_{1}^{2} + d_{2}^{2}}$
$40 = 2 \sqrt{16^{2} + d_{2}^{2}}$
$400 - 256 = d_{2}^{2}$
$144 = d_{2}^{2}, d_{2} = 12 c m$

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The perimeter of a rhombus is 40cm and the length of one diagonal is 16cm. Find the length of the other diagonal.

The correct option is A 12cmPerimeter=4side=412√d21+d2240=2√162+d22400−256=d22144=d22,d2=12cm

The perimeter of a rhombus is $40 c m$ and the length of one diagonal is $16 c m$ . Find the length of the other diagonal.

The correct option is A $12$ cm
Perimeter $= 4 s i d e = 4 \frac{1}{2} \sqrt{d_{1}^{2} + d_{2}^{2}}$
$40 = 2 \sqrt{16^{2} + d_{2}^{2}}$
$400 - 256 = d_{2}^{2}$
$144 = d_{2}^{2}, d_{2} = 12 c m$