Question

The perimeter of a rhombus is $40cm$. If the length of one of its diagonals be $12cm$, then the length of the other diagonal is

• A. $14cm$
• B. $15cm$
• C. $16cm$
• D. $12cm$

Answer 1

Answer: (C)

$16cm$

Each side of the rhombus = $\frac{40cm}{4}=10cm$
Length of the other diagonal $=2\times \sqrt{{10}^2-{\left(\frac{12}{2}\right)}^2}$
$=2\times \sqrt{100-36}=2\times \sqrt{64}cm=16cm.$