Question

The perimeter of a room is $19.50metres$.The length of the room is $6.5m$, find its area.

Answer 1

Here, the room is in the shape of a rectangle.

So, the perimeter of a room $=2(length+breadth)$

Given here, the perimeter of a room is $19.50metres$

And the length of the room is $6.5m$,

therefore on putting the respective values we get:

$$\begin{gathered} 19.50m=2(6.5+b) \\ \frac{19.50}{2}m=(6.5+b) \end{gathered}$$

$$\begin{gathered} 9.75-6.5=b \\ b=3.25m \end{gathered}$$

So, the area of the room $=length\times breadth$

$=3.25\times 6.5$

$=21.125m^2$

Hence, the area of room $=21.125m^2$