Question

The perimeter of a trapezium is $52$ cm and its non-parallel sides are each equal to $10cm$. If its altitude is $8cm$, what is its area?

• A. $128c{m}^2$
• B. $112c{m}^2$
• C. $118c{m}^2$
• D. $124c{m}^2$

Answer 1

Answer: (A)

$128c{m}^2$

Perimeter $=52$ cm

$\Rightarrow AB+BC+CD+DA=52$

$\Rightarrow AB+10+CD+10=52$

$\Rightarrow AB+DC=32cm$

Area of trap $=\frac{1}{2}(AB+DC)\times AM=\frac{1}{2}\times 32\times 8=128{cm}^2$