The perimeter of a trapezium is $52 c m$ and its non-parallel sides are each equal to $10 c m$ and its altitude is $8 c m$ its Area $= ?$

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Solution

Perimeter $= 52 c m$
$a + b + 10 + 10 = 52$
$a + b = 32 c m$
$h = 8 c m$
Area $= \frac{1}{2} (a + b) \times h$
Area $= \frac{1}{2} \times 32 \times 8 = 128 c m^{2}$

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The perimeter of a trapezium is 52cm and its non-parallel sides are each equal to 10cm and its altitude is 8cm its Area =?

Perimeter =52cma+b+10+10=52a+b=32cmh=8cmArea =12(a+b)×hArea =12×32×8=128cm2

The perimeter of a trapezium is $52 c m$ and its non-parallel sides are each equal to $10 c m$ and its altitude is $8 c m$ its Area $= ?$

Perimeter $= 52 c m$
$a + b + 10 + 10 = 52$
$a + b = 32 c m$
$h = 8 c m$
Area $= \frac{1}{2} (a + b) \times h$
Area $= \frac{1}{2} \times 32 \times 8 = 128 c m^{2}$