wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

The perimeter of a ABC is 3 times the arithmetic mean of sine of its angles.

If the side b=1, then find the angle B

A
π6
No worries! We‘ve got your back. Try BYJU‘S free classes today!
B
π3
No worries! We‘ve got your back. Try BYJU‘S free classes today!
C
π2
Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses
D
none of these
No worries! We‘ve got your back. Try BYJU‘S free classes today!
Open in App
Solution

The correct option is B π2
Given:
s=3sinA+sinB+sinC3=sinA+sinB+sinC

Multiplying 2R on both sides
2Rs=2R(sinA+sinB+sinC).........................(1)

we know that, a=2RsinAb=2RsinBc=2RsinC

Putting these values in (1) we get,
2R(a+b+c)=a+b+cR=12

Again from sine Rule,
bsinB=1sinB=b

Since, b=1(Given)
sinB=1B=90o

Therefore, Answer is π2

flag
Suggest Corrections
thumbs-up
0
Join BYJU'S Learning Program
similar_icon
Related Videos
thumbnail
lock
Area
MATHEMATICS
Watch in App
Join BYJU'S Learning Program
CrossIcon