The perimeter of a triangle is $24 c m$ . The length of the its sides are consecuctive integer. Find its sides.

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Solution

Let $x, (x + 1)$ and $(x + 2)$ be the sides of given triangle.

Therefore,

Perimeter of triangle $= a + b + c = 24 c m (Given)$
$x + (x + 1) + (x + 2) = 24$
$3 x + 3 = 24$
$\Rightarrow x = \frac{24 - 3}{3} = 7$
Therefore,
Sides of triangle are $7, 8$ and $9 c m$ respectively.

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The perimeter of a triangle is 24 cm. The length of the its sides are consecuctive integer. Find its sides.

Let x,(x+1) and (x+2) be the sides of given triangle.Therefore,Perimeter of triangle =a+b+c=24cm(Given)x+(x+1)+(x+2)=243x+3=24⇒x=24−33=7Therefore,Sides of triangle are 7,8 and 9cm respectively.

The perimeter of a triangle is $24 c m$ . The length of the its sides are consecuctive integer. Find its sides.

Let $x, (x + 1)$ and $(x + 2)$ be the sides of given triangle.

Therefore,

Perimeter of triangle $= a + b + c = 24 c m (Given)$
$x + (x + 1) + (x + 2) = 24$
$3 x + 3 = 24$
$\Rightarrow x = \frac{24 - 3}{3} = 7$
Therefore,
Sides of triangle are $7, 8$ and $9 c m$ respectively.